Evaluating Arithmetic Expressions

Given the following values indicated how each expression would be evaluated?

Treat each expression separately, using the original values stated at the top and side.

intA = 2 intB = 4 intC = 3 intD = 11

Expression	Result
intA + intB ^ 2	Answer = 18 4 squared = 16 16 + 2 = 18
8 / intB / intA	Answer = 1 8 / 4 = 2 2 / 1 = 1
intA * (intA + 1)	Answer = 6 2 + 1 = 3 operation inside parenthesis occur first 2 * 3 = 6
intA * intA + 1	Answer = 5 2 * 2 = 4 4 + 1 = 5
intB - intA + intC * 2	Answer = 8 3 * 2 = 6 multiplication happens before subtraction or addition 4 – 2 = 2 2 + 6 = 8
intD mod intB	answer = 3 Modulus returns the remainder after division of the two operands. 4 goes into 11 2 times with a remainder of 3.	intA 2 intB 4 intC 3  intD 11
intB - (intA + intC) * 2	Answer = -6 2 + 3 = 5 operation inside parenthesis occur first 5 * 2 = 10 multiplication happens before subtraction or addition 4 - 10 = -6
intD \ intA + intA	Answer = 7 integer division (\) returns an integer and discards the remainder or decimal so 11 \ 2 = 5 5 + 2 = 7
(intB - intA) + intC * 2	Answer = 8 4 – 2 = 2 operation inside parenthesis occur first 3 * 2 = 6 multiplication happens before subtraction or addition 2 + 6 = 8
intB * intB \ intC	answer = 5 4 * 4 = 16 16 \ 3 = 5 integer division (\) returns an integer and discards the remainder or decimal
intC * 5 mod intA	Answer = 1 multiplication has precedence over modulus (remainder) 15 mod 2 = 1
((intB - intA) + intC) * "2"	Visual Basic will evaluate this to 10 However the statement is an INVALID statement, you must not do arithmetic with nonnumeric constants (anything in quotes)
intD \ intC	Answer = 3 integer division (\) returns an integer and discards the remainder or decimal. 3 goes into 11 three times.
intD mod intA + intA	Answer = 3 Modulus (which returns the remainder from division) is evaluated first. 11 mod 2 equal 1 1 + 2 = 3